>[!question] >Determine the limit of the sequence, or show that the limit diverges. $\huge a_n=\frac{6 n^2+n+2}{13 n^2-3}$ $\huge \begin{align} \lim_{n\to\infty} a_n&= \lim_{n\to\infty} \frac{6 n^2+n+2}{13 n^2-3} \\ &= \frac{6}{13} \end{align}$