$\huge \int_{-3}^{3} \frac{1}{x+8} \d x $ $\huge \begin{align} \let u &= x+8 \\ \let \d u &= \d x \\ &= \int_{{5}}^{11} u^{-1} \\ &= \ln 11 - \ln 5\\ &= \ln \frac{11}{5} \end{align} $