Let $y$ be a [[Function]] of $t$. $\huge \begin{align} y'(t) &= \frac{y^{2}}{t+1}\\ y(0) &= 2 \\ \end{align}$ $ \begin{align} \frac{dy}{dt} &= \frac{y^{2}}{t+1} \\ \int \end{align}$